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You are here  >  Home : U_Science  >  U_Mathematics  >  Cyclic Numbers, Fractal Algebra, Universal Algebra...  >  In the paradigm of the TOTAL Universe, we can now divide by zero!

In the paradigm of the TOTAL Universe, we can now divide by zero!

The problem of the division by 0: a problem of paradigm and of conception of the Universe

Nombres cycliques Nombres cycliques

In the paradigm of cyclical numbers (that is also the paradigm of equivalence), any number ω satisfies the equality (and precisely the equivalence) : 0 = ω. Therefore, we call this the Cycle ω.

In the Cycle ω, we simply have :
1/0 = ω et 1/ω = 0.
And also, the equality of the cycle, namely 0 = ω, leads to this amazing result : 1/0 = 0.

For example, in the cycle 4 that is written 0 = 4, we have : 1/0 = 4 et 1/4 = 0.
And in the cycle 564725 that is written 0 = 564725, we have : 1/0 = 564725 et 1/564725 = 0.

We must also notice that in the paradigm of Cycle, the notions of infinity and of variable (or unknown) are the same notion.

For example, let us consider this equation :
X = X + X

In the classical algebra (non cyclical algebra), solving this equation leads to the solution :
X = 0
and we were usually saying that the single solution of that équation is 0.

But in the cyclical algebra, the variable (or unknown) X is also an infinite number, we can call ω. So in fact we have (at least) two solutions for that equations, 0 and ω. In other words, we have two extreme numbers that satisfy this kind of equality :
X = X + X .
First we have 0 :
0 = 0 + 0
and at the other extreme we have the infinity ω:
ω = ω + ω.

In other words, the result X = 0 is simply the expresiion of the cycle X, namely 0 = X. In the cyclical algebra, we directly solve equations with the infinite number ω. So we solve this :
ω = ω + ω
and we get this result : ω = 0 or 0 = ω, that is simple expression of Cycle ω.

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